3(x^2+2)-5=28

Solution for 3(x^2+2)-5=28 equation:

Simplifying
3(x2 + 2) + -5 = 28

Reorder the terms:
3(2 + x2) + -5 = 28
(2 * 3 + x2 * 3) + -5 = 28
(6 + 3x2) + -5 = 28

Reorder the terms:
6 + -5 + 3x2 = 28

Combine like terms: 6 + -5 = 1
1 + 3x2 = 28

Solving
1 + 3x2 = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3x2 = 28 + -1

Combine like terms: 1 + -1 = 0
0 + 3x2 = 28 + -1
3x2 = 28 + -1

Combine like terms: 28 + -1 = 27
3x2 = 27

Divide each side by '3'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}